Question

plz send it solution​

Answer 1

Answer:

option: (3)

Explanation:

$x = -2 {t}^{3} + 3 {t}^{2} + 5 \\ v = \frac{dx}{dt} = - 6 {t}^{2} + 6t \\ v = 0 \\ - 6 {t}^{2} + 6t = 0 \\ - 6t(t - 1) = 0 \\ t = 0 \: \: and \: \: t = 1 \\ a = \frac{dv}{dt} = - 12t + 6 \\ putting \: \: value \: \: of \: \: t \\ a = 6ms^{ - 2} \: and \: - 6ms^{ - 2}$

Answer 2

Answer:

-6m/s^2

Explanation:

velocity v=dx/dt=0

-6t^2+6t=0

6t(-t+1)=0

t=1sec

now acceleration of the particle

a=dv/dt

-12t+6

-12(1)+6

=-6m/s^2