Question

plz send me ans of this que ppz guys faster​

Answer 1

Answer:

1

$\frac{ log(a) }{x + y - 2z} = \frac{ log(b) }{z + y - 2x} = \frac{ log(c) }{z +x - 2y} = k \: \: (let) \\ \\ log(a) = k({x + y - 2z}) \\ log(b) = k({z + y - 2x}) \\ log(c) = k({x + z- 2y}) \\ + \: \: \: \: \: \: \: \: \: \: \: \: \: \: + \\ - - - - - - - - - - - \\ log(a) + log(b) + log(c) = k(2x + 2y + 2z - 2x - 2y - 2z) \\ log(abc) = 0 \\ abc = 1$