Question

Plz send me answer. It am unable to solve it.​

Answer 1

Qᴜᴇsᴛɪᴏɴ :-

A says to B "I am twice as old as you were when I was as od as you are now". The sum of their present ages is 77 years. find their Present age ?

Sᴏʟᴜᴛɪᴏɴ :-

Let A’s present age be x years old.

Then,

→ B’s present age = (77 - x)

And ,

→ when A = (77 - x)

→ A - B = (2x - 77)

→ (77 - x) - B = (2x - 77)

→ B = 77 - x - 2x + 77

→ B = (154 - 3x)

Also, we have given that, A’s age is twice as B’s.

so,

→ x = 2(154 - 3x)

→ x = 2*154 - 6x

→ x + 6x = 2*154

→ 7x = 2*154

→ x = 2*22

→ x = 44 Years.

Hence,

→ A’s Present age = x = 44 Years.

→ B’s Present age = 77 - 44 = 33 Years.

Answer 2

Let the present age of A be " x "

So the present age of B be " 77 - x "

Since it is given that " Sum of their ages is 77 years "

Now

( A - B ) = x - ( 77 - x )

⇒ A - B = 2x - 77

⇒ ( 77 - x ) - B = 2x - 77

⇒ B = 154 - 3x

Now A is twice as B

⇒ A = 2B

⇒ x = 2 ( 154 - 3x )

⇒ x = 308 - 6x

⇒ 7x = 308

⇒ x = 44

Present age of A = x = 44 years

Present age of B = ( 77 - x ) = 33 years