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Answers
Step-by-step explanation:
Sol 1 Consider Aftab's age as x and his daughter's age as y.
Then , seven years ago,
Aftab's age =x−7
His daughter's age =y−7
According to the question,
x−7=7(y−7)
x−7=7y−49
x−7y=−49+7
x−7y=−42 …(i)
After three years,
Aftab's age =x+3
His daughter's age =y+3
According to the question,
x+3=3(y+3)
x+3=3y+9
x−3y=9−3
x−3y=6 …(ii)
Representing equation (i) and (ii) geometrically, we plot these equations by finding points on the lines representing these two equations
x−7y=−42⟹x=7y−42
x=7y−42 42 35 49
y 12 11 13
x−3y=6⟹x=3y+6
x=3y+6 42 36 48
y 12 10 14
From the graph we can see that two lines will intersect at a point.
x−7y=−42
x−3y=6
On subtracting the two equations, we get
4y=48
or y=12
Substituting value of y in (2),
x−36=6
∴x=42
Sol 2 Let the price of one Bat be x and the price of one ball be y,
Now, According to the question,
From(1) we have
By putting different values of x, we get different corresponding values of y.So
X 100 300 -100
Y 600 500 700
Now, From (2), we have,
By putting different values of x, we get different corresponding values of y.So
X 100 400 -200
Y 400 300 500
Sol 3
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What is your question?
1
sada7254
09.12.2018
Math
Secondary School
+13 pts
Answered
The cost of 2kg of apples and 1 kg of grapes on a day was found to be 160rs. After a month, the cost of 4kg of apples and 2kg of grapes is 300rs. Represent the situation algebraically and geometrically.
2
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atharva24112003
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Answer:
Step-by-step explanation:
let us consider that price of apple be x & grapes be y
case1:
2x+y=160 ..............eq1
case 2:
4x+2y=300 .......................eq2
divide equation 2 on both side by 2
2x+y=150 ..............................eq 3
we got two equations 1&3
2x+y=160 &2x+y=150
then put simanteniously x and y values
in eq 1 in eq 3
2x+y=160 2x+y=150
x=50 x=50
100+y=160 100+y=150
y=60 y=50
x=30 x=30
60+y=160 60+y=150
y=100 y=90
