Question

plz send process and answer

Answer 1

Answer:

(d)  2

Hope this helps.

Step-by-step explanation:

$\displaystyle 60^b=5 \Rightarrow 60^{-b} = \tfrac15 \Rightarrow 60^{1-b}=60\times\tfrac15=12\\ \\\Rightarrow 12^{\frac{1}{1-b}} = 60\\ \\\Rightarrow 12^{\frac{1-a-b}{1-b}} = 60^{1-a-b} = \frac{60}{60^a\times60^b}=\frac{60}{3\times 5} = 4\\ \\\Rightarrow 12^{\frac{1-a-b}{2(1-b)}} = 4^{\frac12} = \sqrt4 = 2$