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TSA of solid=TSA of cbe+CSA of hemisphere- are of circle
=6a^2+2πr^2-πr^2
=6a^2+πr^2
=6×(6)^2+22\7×2.1×2.1
=216+13.85
=229.85cm^2
Now, volume of solid
= Volume of cube+volume of hemisphere
=a^3+2/3πr^3
6^3+2/3×22/7×2.1×2.1×2.1
=216+19.404
=235.404cm^3
pathakabhishek625:
Hope it is helpful........
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a) total surface Area of block is 229.86cm².
b) volume of block is 235.404cm³.
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