Question

show that -3/2 and -3 are zeroes of the polynomial 6x³+23x²+9x-18

Answer 1

Answer:if we put value of X and get 0 then these are roots of equation.

Now firstly we put x= -3/2 and check it.

6×(-3/2)^3 + 23 (-3/2)^2 + 9 (-3/2) -18

-81/4 + 207/4 - 27/2 -18

(-81 + 207 - 54 - 72)/4

0/4

= 0

This is the zero of polynomial.

Now we put x = -3

- 27 (6) + 23 (9) - 27 -18

-162 + 207 -27 - 18

= 0

Hence proved, both are the zeros of polynomial.

Step-by-step explanation: