Question

plz send the answer with full fledge explanation​

Answer 1

ANSWER = 3

$\huge\sf\underline{\underline{ Given }}$

$\sf{If \: \: {x}^{ - 2} } = 64 \: find \: {x}^{ (\frac{1}{3}) } + {x}^{0}$

$\huge\sf\underline{\underline{ Answer }}$

STEP : 1

• Find value of 'x'

$• \: {x}^{ - 2} = 64$

$• \: \frac{1}{ {x}^{2} } = 64$

$• \: {x}^{2} = \frac{1}{64}$

$• \: x = \sqrt{ \frac{1}{64} }$

$• \: x = \frac{1}{8}$

STEP :2

• Apply the value of x to the equation

$[ {x}^{ \frac{1}{3} } = \sqrt[3]{x} \: \: and \: \: {x}^{0} = 1 ]$

$\large\sf • \: {x}^{ \frac{1}{3} } + {x}^{0}$

$\: \: \: \: \: \: = \sqrt[3]{8} + 1$

$\: \: \: \: \: \: = 2 + 1$

$\: \: \: \: \: \: = 3$

$\huge\sf\underline{\underline{ Formulas \: used }}$

$• \: a^{-1} = \frac{1}{a}$

$• \: x^{\frac{1}{3} } = \sqrt[3]{x}$

$• \: a^{0} = 1$