plz slove ques. no. 31 plz....
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Given f(x) = x^3 - 10x^2 + ax + b
Given that (x - 1) is a factor of f(x).Therefore f(1) = 0
= > f(1) = (1)^3 - 10(1)^2 + a(1) + b = 0
= > 1 - 10 + a + b = 0
= > a + b = 9 ------ (1)
Given that (x - 2) is a factor of f(x), we get f(2) = 0
= > f(2) = (2)^3 - 10(2)^2 + a(2) + b = 0
= > 8 - 40 + 2a + b = 0
= > 2a + b = 32 ------ (2)
On solving (1) & (2),we get
2a + b = 32
a + b = 9
--------------------
a = 23.
Substitute a = 23 in (1), we get
= > a + b = 9
= > 23 + b = 9
= > b = -14.
Therefore the value of a = 23, b = -14.
Hope this helps!
Given that (x - 1) is a factor of f(x).Therefore f(1) = 0
= > f(1) = (1)^3 - 10(1)^2 + a(1) + b = 0
= > 1 - 10 + a + b = 0
= > a + b = 9 ------ (1)
Given that (x - 2) is a factor of f(x), we get f(2) = 0
= > f(2) = (2)^3 - 10(2)^2 + a(2) + b = 0
= > 8 - 40 + 2a + b = 0
= > 2a + b = 32 ------ (2)
On solving (1) & (2),we get
2a + b = 32
a + b = 9
--------------------
a = 23.
Substitute a = 23 in (1), we get
= > a + b = 9
= > 23 + b = 9
= > b = -14.
Therefore the value of a = 23, b = -14.
Hope this helps!
siddhartharao77:
:-)
Answered by
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i hope it will be helpful.......
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