Question

plz slove that math

Answer 1

$\frac{a}{ax - 1} + \frac{b}{bx - 1} = a + b \\ solving \: lhs \\ \frac{a(bx - 1) + b(ax - 1)}{(ax - 1)(bx - 1)} = a + b \\ \frac{2abx - a - b}{(ax - 1)(bx - 1)} = a + b \\ 2abx - a - b = (a + b)(ab {x}^{2} - x(a + b) + 1)$
$\frac{a}{ax - 1} + \frac{b}{bx - 1} = a + b \\ solving \: lhs \\ \frac{a(bx - 1) + b(ax - 1)}{(ax - 1)(bx - 1)} = a + b \\ \frac{2abx - a - b}{(ax - 1)(bx - 1)} = a + b \\ 2abx - a - b = (a + b)(ab {x}^{2} - x(a + b) + 1) \\ \frac{2abx}{a + b} - 1 = ab {x}^{2} - x(a + b) + 1$

solve this... or if u want me to solve this comment me...