Question

plz slve this for claass 9th studnt

Answer 1

Let x = 0.131 bar (bar on 31)
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10 × x = 10 × 0.131 (bar)

10x = 1. 31 bar 
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As there are 2 [3 and 1] under bar, multiply by 100.
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100 × 10x = 100 × 1.31 bar 

1000x = 131 .31 bar
   -10x =   -1.31 bar [subtracting 10x]
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990x = 130  [bar cancelled]
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x =$\frac{130}{990} = \frac{13}{99}$


Now,

0.131 (bar) = $\frac{13}{99}$




i hope this will help you



-by ABHAY

Answer 2

Hello dear friend ,

Sol.

$let \: \: x = 0.1313131....(bar \: on \: 31) \: \: ......(1) \\ first \: of \: all \: multiply \: by \: 100 \\ \\ 100x = 13.13131...... \: \: \: \: \: \: \: \: \: \: \: \: ...... (2) \\ \\ no w \: subtract \: (2) \: from \: (1) \\ \\ = > 100x - x = (13.13131....) - (0.13131....) \\ \\ = > 99x = 13 \\ \\ = > x = \frac{13}{99}$
Hope it's helps you

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