plz solve 11 ,12,13and 14 question fast plz
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11)
Time = Total rupee / Rate of spending
= (6.022 * 10*23) / (10 * 10^5)
= 6.022 * 10^17 seconds
= 6.022 * 10^17 seconds * 1/(31536000 seconds/year)
= 1.90 * 10^10 year
12)
Moles of CaCl2 = 222/110 = 2.0 mole
Number of Ca+ ions in 2.0 mole of CaCl2 = 2N
Number of moles of Cl- ions in 2.0 moles of CaCl2 = 4N
Ratio of Cl- ions to Ca+ ions = 4 : 2
13)
Percentage of sulphur = Weight of sulphur / Molecular weight of insulin * 100
Molecular weight of insulin = wieght of sulphur * 100 / percentage of sulphur
= 32 * 100 / 3.4
= 941.76
14)
Moles of
34g of water = 34/18 = 1.8 mol
28g of CO2 = 28/44 = 0.6 mol
46g of CH3OH = 46/32 = 1.4 mol
54g of N2O5 = 54/108 = 0.5 mol
Hence 34g of water has largest number of molecules.
Time = Total rupee / Rate of spending
= (6.022 * 10*23) / (10 * 10^5)
= 6.022 * 10^17 seconds
= 6.022 * 10^17 seconds * 1/(31536000 seconds/year)
= 1.90 * 10^10 year
12)
Moles of CaCl2 = 222/110 = 2.0 mole
Number of Ca+ ions in 2.0 mole of CaCl2 = 2N
Number of moles of Cl- ions in 2.0 moles of CaCl2 = 4N
Ratio of Cl- ions to Ca+ ions = 4 : 2
13)
Percentage of sulphur = Weight of sulphur / Molecular weight of insulin * 100
Molecular weight of insulin = wieght of sulphur * 100 / percentage of sulphur
= 32 * 100 / 3.4
= 941.76
14)
Moles of
34g of water = 34/18 = 1.8 mol
28g of CO2 = 28/44 = 0.6 mol
46g of CH3OH = 46/32 = 1.4 mol
54g of N2O5 = 54/108 = 0.5 mol
Hence 34g of water has largest number of molecules.
Yugandharanangare:
thanks very much
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