Math, asked by niranbaro72, 11 months ago

Plz.Solve.............

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Answers

Answered by Anonymous
1

a²+b²+c² -ab-bc-ca = 0

(a+b+c)² = a²+b²+c² -ab-bc-ca

so we can write

(a+b+c)²=0

√(a+b+c)²=√0

a+b+c=0

a=0

b=0

c=0

then

a= b=c

hope it helps

Check it once

Answered by dixitamalik2510
1

ANSWER:

we can take  a^2+b^2+c^2 as R.H.S. and ab+bc+ca as L.H.S.

we take -ab-bc-ca in positive values b/s negative values change into positive values when they go after =

R.H.S.                                    L.H.S.

a^2+b^2+c^2 = ab+bc+ca

a×a+b×b+c×c = a×b+b×c+c×b

if we try to cut it,

then our  whole equation will cut.

we can say that R.H.S.=R.H.S.

therefore, we can say a=b=c

I hope it will help

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