Plz solve 1st question....
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Hey miss
✡here is ur answer ✡
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An object moving in a circle is accelerating. Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction.
An object undergoing uniform circular motion is moving with a constant speed. Nonetheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards.
This acceleration is a radial acceleration since it is always directed toward the centre of the circle and takes the magnitude:
A=V^2/R
where V is the object's linear speed along the circular path.
Equivalently, the radial acceleration vector A
may be calculated from the object's angular velocity w
A=. -W^2R
where. R is a vector directed from the centre of the circle and equal in magnitude to the radius. The negative shows that the acceleration vector is directed towards the centre of the circle (opposite to the radius).
So there is no change in acceleration i.e the acceleration is constant for uniform circular motion.
✡✡✡✡✡✡✡✡✡✡✡✡✡✡
I hope it helps
#Prem✌❤
✡here is ur answer ✡
▶▶▶▶▶▶▶▶▶▶▶
An object moving in a circle is accelerating. Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction.
An object undergoing uniform circular motion is moving with a constant speed. Nonetheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards.
This acceleration is a radial acceleration since it is always directed toward the centre of the circle and takes the magnitude:
A=V^2/R
where V is the object's linear speed along the circular path.
Equivalently, the radial acceleration vector A
may be calculated from the object's angular velocity w
A=. -W^2R
where. R is a vector directed from the centre of the circle and equal in magnitude to the radius. The negative shows that the acceleration vector is directed towards the centre of the circle (opposite to the radius).
So there is no change in acceleration i.e the acceleration is constant for uniform circular motion.
✡✡✡✡✡✡✡✡✡✡✡✡✡✡
I hope it helps
#Prem✌❤
sharpyy:
its right na
its d option
u tried to help me so i thanked u
ooops
ohhk ohk
let me edit
ah sorry miss but mera answer alag aaya abhi bhi
koi baat ni
v^2-u^2=2as ismevalues
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