Question

plz solve................. ​

Answer 1

$\huge\underline{\bf \orange{Solution :}}$

By using quadratic formula

$\implies \boxed{\sf x = \dfrac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}}$

Here

• a = 7
• b = 2√14
• c = 2

Substitute values in formula

$\implies \tt x = \dfrac{ - 2 \sqrt{7} \pm \sqrt{ {(2 \sqrt{7}) }^{2} - 4 \times 7 \times 2} }{2 \times 7} \\ \\ \implies \tt x = \dfrac{ - 2 \sqrt{7} \pm \sqrt{28 - 56} }{14} \\ \\ \implies \tt x = \dfrac{ - 2 \sqrt{7} \pm \sqrt{ - 28} }{14}$

Taking +ve sign

$\implies \tt x = \dfrac{ - 2 \sqrt{7} + \sqrt{ - 28} }{14}$

Taking - ve sign

$\implies \tt x = \dfrac{ - 2 \sqrt{7} - \sqrt{ - 28} }{14}$