Question

plz solve ..............

Answer 1

answer:

3.6Ω.

Explanation:

The equivalent resistance between A & B and A &C are 2.4Ω and 3.6Ω respectively.

In between A & B, the path AB & ACB forms a parallel combination.

along the path ACB, the resultant resistance = 6+6 = 12Ω.

along path AB, the resultant resistance = 3Ω.

The resultant resistance about A & B = \frac{12*3}{12+3}

12+3

12∗3

Ω = \frac{36}{15}

15

36

Ω= 2.4Ω

In between A & C, the path AC and ABC forms a parallel combination.

Along the path AC, the resultant resistance = 6Ω.

Along the path ABC, the resultant resistance = 6+3Ω = 9Ω.

The resultant resistance about A & C = \begin{gathered}\frac{9*6}{9+6}=\frac{54}{15}\\\end{gathered}

9+6

9∗6

=

15

54

= 3.6Ω.