Question

plz solve all questions
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Answer 1

$GIVEN:$
➡AP=PB
➡ angle BAD= angle ABE
➡angle EPA= angle DPB

$TO. PROVE:$
a) ∆ DAP = ∆ EBP
b) AD=BE

$PROOF:$
i) ✡In ∆ DAP and ∆ EBP ...
AP=PB (given)
angle BAD = angle ABE (given)
angle EPA = angle DPB (given)
Therefore, adding angle EPD on both side :
angle EPA + angle EPD = angle DPB + angle EPD
hence, angle APD = angle APB

By ASA ,
∆DAP is congruent to ∆EBP.

ii) AD = BE (CPCT)

Hence proved !

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