Plz solve all the questions from 4 to 11
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l×b=area of rect.
3+b×b=54
3b+b²=54
b²+3b-54=0
b²+9b-6b-54=0
b(b+9)-6(b+9)=o
b=6or -9
3+b×b=54
3b+b²=54
b²+3b-54=0
b²+9b-6b-54=0
b(b+9)-6(b+9)=o
b=6or -9
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