plz solve and explain and I will mark it as brainliest
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SOLUTION
Given A=(1223)A2−kA−I2=0
→A2=(1223)(1223)=(58810)
A2−kA−I2=[58813]−k[1223]−[1001]
=[48812]−k[1223]=0
=[4−k8−k8−2k12−3k]=0
∴4−k=0⇒k=4
12−3k=0⇒k=4
∴k=4.
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