Math, asked by dilpreetsingh3336, 1 month ago

plz solve and explain and I will mark it as brainliest​

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Answers

Answered by sunprince0000
0

ANS.

4

SOLUTION

Given A=(1223)A2−kA−I2=0

→A2=(1223)(1223)=(58810)

A2−kA−I2=[58813]−k[1223]−[1001]

=[48812]−k[1223]=0

=[4−k8−k8−2k12−3k]=0

∴4−k=0⇒k=4

12−3k=0⇒k=4  

∴k=4.

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