Plz solve ASAP... plz try to give full nd clear explaination....
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Answer:
take ,Tan = as sinA / cos A
and, Cot = cos A / sin And then solve hope your answer will come
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Answer:
tan²A + cot² = sec²A cosec²A -2
LHS [Identity → 1+ tan²A = sec²A
= sec²A - 1 + cot²A tan²A= sec²A -1]
= sec²A - 1 +cosec²A -1 [Identity → 1+ cot²A = cosec²A
= ( 1/cos²A + 1/sin²A) -2 cot²A= cosec²A -1]
= ( sin²A + cos²A / cos²Asin²A)-2
= (1/ cos²A sin²A) -2
= sec²A cosec²A - 2 [ Identity → 1/cos A = sec A, 1/sin A = cosec A]
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