Math, asked by Myira1, 1 year ago

plz solve both of the questions ...
plz fast....

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Answers

Answered by Tausif11111
0
i think Q19 Answer will be 2005

Tausif11111: oops it will be 2015
Answered by siddhartharao77
1
19.

Given that his salary in 1995 = 5000.

Given that he received an increment of rs.200 in every year.

5000,5200,5400,5600,5800........

Let  a be the first term and d be the common difference.

a = 5000, d = 200.


We know that an = a + (n - 1) * d

                         7000 = 5000 + (n - 1) * 200

                         7000 = 5000 + 200n - 200

                         7000 = 4800 + 200n

                         7000 - 4800 = 200n

                         2200 = 200n

                         n = 2200/200

                         n = 11.


Therefore in 11th year, his income reached to 7000.




(20)

Given Ramkali saved rs.5 in the first week of a year and increased her savings by 1.75.

First term a = 5,

common difference d =1.75

an = 20.75

We know that an = a + (n - 1) * d

                        20.75 = 5 + (n - 1) * 1.75

                        20.75 = 5 + 1.75n - 1.75

                        20.75 = 3.25 + 1.75n

                       n = 17.5/1.75

                       n = 10.


Therefore in nth week, her savings become rs.10.


Hope this helps!

siddhartharao77: Brainliest it if possible
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