Question

plz solve fast and i will ask doubt if any
ques. 3

Answer 1

Hey !!!


Given . tan ( A + B ) = √ 3

and tan ( A - B ) = 1/√3

Since , we know √3 = tan60° and 1/√3 = tan30°

tan ( A + B ) = tan60°

(A + B ) = 60 ° ______1)

Again, tan ( A - B ) = tan30°

( A - B ) = 30° __________2)

Adding both equation .

A + B = 60°
A - B = 30°
__________
2A = 90°

A = 45°

putting the value of A on 1st equation .

A + B = 60°

45° + B = 60°

B = 15°

Hence , value of A and B , 0° < A + B <90° is 45° and 15° respectevely

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Hope it helps you !!!

@Rajukumar111

Answer 2

HEYA!!
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Given that ,

Tan ( A + B ) = √3

Tan ( A - B ) = 1/√3


➡Tan is √3 at 60 °

➡Tan is 1/√3 at 30°


So we have ,


A + B = 60°----------------------------------------------------(1)

A - B = 30°---------------------------------------------------(2)

Adding (1) and (2)


2A = 90


A = 45°

Putting A = 45 in (1)

45 + B = 60

B =15°


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