Question

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Answer 1

Answer:

$let \: the \: first \: no. \: be \: x \\ \\ let \: the \: second \: no. \: be \: y \\ \\ \implies \: x = 5y \\ \\ after \: adding \: 21 \: to \: both \: of \: the \: no.s \\ \\ is \: y + 21 \\ \\ and \: x + 21 \\ \\ \implies 5x + 21 = 2(y + 21) \\ \\ \implies \: 5y + 21 = 2y + 42 \\ \\ \implies5y - 2y = 42 - 21 \\ \\ \implies3y = 21 \\ \\ \implies \: y = \frac{21}{3} \\ \\ \implies \: y = 7 \\ \\ now \: \: x = 5y \\ \\ \implies \: x = 5 \times 7 \\ \\ \implies \: x = 35 \\ \\ hence \: x = 35 \: and \: y = 7 \: \: \: answer$

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Answer 2

$\huge \pink{ \underline{ \mathtt{x= 35 ,y =7}}}$