plz solve for this function
the first to answer will be marked as brainlest
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Given f(x)=x^2-3x+4=f(2x+1)
X^2-3x+4=(2x+1)^2-3(2x+1)+4
X^2-3x+4=2(x^2)+1+4x-6x-3+4
2(x^2)-2x+2-x^2+3x-4=0
X^2+x-2=0
X^2-1x+2x-2=0
X(x-1)+2(x-1)=0
(x+2)(x-1)=0
x+2=0 (OR) x-1=0
x=-2 (OR) x=1
X^2-3x+4=(2x+1)^2-3(2x+1)+4
X^2-3x+4=2(x^2)+1+4x-6x-3+4
2(x^2)-2x+2-x^2+3x-4=0
X^2+x-2=0
X^2-1x+2x-2=0
X(x-1)+2(x-1)=0
(x+2)(x-1)=0
x+2=0 (OR) x-1=0
x=-2 (OR) x=1
grishmamody:
Ur answer is actually wrong
The answer should be -1 and 2/3
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