Question

Plz solve it.

ax^2 + (b + ac) x + bc by x + c

Answer 1

ax^2 + bx + acx + bc / x + c
x ( ax + b ) + c ( ax + b ) / x + c
( x + c ) ( ax + b ) / x + c

x+ c is cut

so the left is our answer
( ax + b )

Answer 2

Hello..
Answer..

We have,

ax^2 + ( b + ac ) x + bc

= ( ax^2 + bx ) + ( acx + bc )

= x ( ax + b )+ c ( ax + b ) = ( ax + b ) (x + c)

Hence: ( ax^2 + ( b + ac ) x + bc divided by ( x + c)

= ax^2 + ( b + ac) x + bc / x + c

= ( ax + b) ( x + c) / ( x + c

= ax + b [ Cancelling common factor ( x + c) in numerator and denominator]

Hope it helped ☺☺☺