Math, asked by kashishnaamdev84, 16 days ago

plz solve it
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Answered by vansh2103
2

Answer:

( {4}^{ - 1}   +  {8}^{ - 1} ) \div  (\frac{2}{3}  {)}^{ - 1}  \\ ( \frac{1}{4}  +  \frac{1}{8} )  \div  \frac{3}{2}  \\  \\  \frac{2 + 1}{8}  \times  \frac{2}{3}  =  \frac{3}{8}  \times  \frac{2}{3}  =  \frac{1}{4}

Answered by utsav96
1
Pls mark as brainliest answer

Answer is 1/4.
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