The overall percentage of failures in a certain examination is 60. to what the probably that out of a group of 6 candidates at Least 5 passed the examination?
Answers
Explanation:
4 5 or 6
p(passed) = .6
p(failed) = .4
Binomial distribution
for example for 4 of 6 passed
C(6,4) .6^4 .4^2
C(6,4) = 6!/[ 4!(2!)] = 6*5/2 = 15
15 * .6^4*.4^2 = .311
do that also for 6,5
and for 6,6
and add those three results
Explanation:
probability that out of 6 candidates, at least 4 Passed = 0.54432
Step-by-step explanation:
the overall percentage of failure in a certain exam is 40.
=> Failure Probability = 40/100 = 0.4 = p Passing probability = 1-0.4 0.6 = q
probability that out of 6 candidates, at least 4 Passed = Probability of 0 Failed + Probability of 1 Failed + Probability of 2 Failed
= "Co(0.4)(0.6) + C(0.4)(0.6) + C₂(0.4)²(0.6)*
= 1 1 (0.6) +6 0.4 (0.6) +15+ 0.16 * (0.6)*
= (0.6) (0.36 + 1.44 +2.4)
= (0.6)* (4.2)
= 0.54432
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