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LHS = (CotA -1) /( 2- Sec²A )
= ( CotA-1) / (1 + 1 - Sec²A)
= (1/tanA)-1 / ( 1 - tan²A) ●Since tan²A +1 = sec²A So, 1- Sec²A = - tan²A
= (1-tanA) / tanA (1+tanA)(1-tanA) ● by identity a² -b² = (a+b) ( a-b)
= 1/ tanA(1+tanA)
= CotA / (1+tanA) = RHS
Hence Proved..
i hope this answer will help you..
= ( CotA-1) / (1 + 1 - Sec²A)
= (1/tanA)-1 / ( 1 - tan²A) ●Since tan²A +1 = sec²A So, 1- Sec²A = - tan²A
= (1-tanA) / tanA (1+tanA)(1-tanA) ● by identity a² -b² = (a+b) ( a-b)
= 1/ tanA(1+tanA)
= CotA / (1+tanA) = RHS
Hence Proved..
i hope this answer will help you..
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