Math, asked by rajgandhij, 1 year ago

plz solve it fast as i need it plz help guys

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Answered by Aashik786
1
LHS = (CotA -1) /( 2- Sec²A )

= ( CotA-1) / (1 + 1 - Sec²A)

= (1/tanA)-1 / ( 1 - tan²A) ●Since tan²A +1 = sec²A So, 1- Sec²A = - tan²A

= (1-tanA) / tanA (1+tanA)(1-tanA) ● by identity a² -b² = (a+b) ( a-b)

= 1/ tanA(1+tanA)

= CotA / (1+tanA) = RHS

Hence Proved..
i hope this answer will help you..

Answered by adityaaryaas
1

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