Question

Plz solve it immediately and correctly . My exam is at 10:30 am plzzzz
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Answer 1

Answer:

256x^{16} - 1 = (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)

Step-by-step explanation:

Given : 256x^{16} - 1

To Find : Factorize

Solution:

256x^{16}-1

16x^8)^2-1^2

(16x^8+1)(16x^8-1)

(16x^8+1)[(4x^4)^2-1^2)]

(16x^8+1)(4x^4+1)(4x^4-1)

(16x^8+1)(4x^4+1)[(2x^2)^2-1^2]

(16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)

Hence 256x^{16} - 1 = (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)