Question

the HCF ×LCM for the numbers 48,72,108​

Answer 1

Step-by-step explanation:

Given numbers are 48, 72 and 108 Factorization of 48, 72 and 108 Here, 22 × 31 are the smallest powers of the common factors 2 and 3 respectively. So, HCF (48, 72, 108) = 2 × 2 × 3 = 12 24 × 33 are the greatest powers of the prime factors 2 and 3 respectively involved in the given three numbers . LCM of these three integers = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 432