plz solve it in a pic plz ..
with explanation ....
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Sum of( 6m²- n²+1) and (4m²-n²)
is (6m²+4m²-n²-n²+1)
(10m²-2n²+1)
The product of (6m+n)&(2m-3n)
is 6m(2m -3n)+n(2m-3n)
(12m²-18mn+2mn-3n²)
The sum of (10m²-2n²+1) & (12m²- 16mn -3n²) is
10m²+12m²-2n²-3n²-16mb+1
(22m²-5n²-16mb+1)
Hope this helps you
Answered by
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hope it helps u
and Plzz mark me as brainlest
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