Math, asked by Akansha3652, 10 months ago

plz solve it in a pic plz ..
with explanation ....​

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Answers

Answered by birupakshya17
1

Sum of( 6m²- n²+1) and (4m²-n²)

is (6m²+4m²-n²-n²+1)

(10m²-2n²+1)

The product of (6m+n)&(2m-3n)

is 6m(2m -3n)+n(2m-3n)

(12m²-18mn+2mn-3n²)

The sum of (10m²-2n²+1) & (12m²- 16mn -3n²) is

10m²+12m²-2n²-3n²-16mb+1

(22m²-5n²-16mb+1)

Hope this helps you

Answered by stushruthi10497
0

hope it helps u

and Plzz mark me as brainlest

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