plz solve it plz( q 30 )
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The cone problem.
Let the height of big cone be H, and radius be R. Those of small cone be h and r respectively.Frustum: H-h is the height.
V = pi/3 R^2 HV = V1 + V2 = 4 V1V1 = volume of small cone = pi/3 r^2 h
We know for the cone: R/r = H/h (similar triangles)So V = pi/3 H^3 r^2/h^2 = * 4 pi/3 r^2 h
H³ = 4 h³H/h = ∛4ratio: h/(H-h) = 1/(∛4 -1) = 1.7
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the capsule prob
capsule = cylinder + one hemisphere + another hemisphere at the other end
length of cylindrical part = L = total length - 2 * radius = 14 - 2 * (5/2) = 9 mm
Total Surface area = Pi r^2 L + 2 pi r^2 + 2 pi r^2
= pi * 2.5^2 * [ 9 + 2 + 2 ] mm^3
= 13 * 6.25 * pi mm^3
Let the height of big cone be H, and radius be R. Those of small cone be h and r respectively.Frustum: H-h is the height.
V = pi/3 R^2 HV = V1 + V2 = 4 V1V1 = volume of small cone = pi/3 r^2 h
We know for the cone: R/r = H/h (similar triangles)So V = pi/3 H^3 r^2/h^2 = * 4 pi/3 r^2 h
H³ = 4 h³H/h = ∛4ratio: h/(H-h) = 1/(∛4 -1) = 1.7
===============
the capsule prob
capsule = cylinder + one hemisphere + another hemisphere at the other end
length of cylindrical part = L = total length - 2 * radius = 14 - 2 * (5/2) = 9 mm
Total Surface area = Pi r^2 L + 2 pi r^2 + 2 pi r^2
= pi * 2.5^2 * [ 9 + 2 + 2 ] mm^3
= 13 * 6.25 * pi mm^3
ChaEunSang:
no down one
30
sry its right
the other qn is also done.
tytyty
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