Question

plz solve it step by step
no one give un nessesary solution

Answer 1

$Given: x = 1 - \sqrt{2}$

$= \ \textgreater \ \frac{1}{x} = \frac{1}{1 - \sqrt{2} } * \frac{1 + \sqrt{2} }{1 + \sqrt{2} }$

$= \ \textgreater \ \frac{1 + \sqrt{2} }{1^2 - ( \sqrt{2})^2 }$

$= \ \textgreater \ \frac{1 + \sqrt{2} }{1 - 2}$

$= \ \textgreater \ \frac{1 + \sqrt{2} }{-1}$

$= \ \textgreater \ \sqrt{2} - 1$


Now,

$= \ \textgreater \ x - \frac{1}{x}$

$= \ \textgreater \ (1 - \sqrt{2} ) - ( \sqrt{2} - 1)$

$= \ \textgreater \ 1 - \sqrt{2} - \sqrt{2} + 1$

$= \ \textgreater \ 2$


Therefore:

= > (x - 1/x)^3 = (2)^3

                      = 8.



Hope this helps!

Answer 2

Your answer is given below