plz solve it step by step. tomorrow is my exam and I don't know this one
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rohan9085:
sorry
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hey mate here is your answer
ax^2+bx+c=0,a=0
The sign of the discriminant (expression under square root in quadratic formula) tells you how many solutions there are for x.
A solution for x means the parabola touches/crosses the x-axis. (Once for one solution, twice for two solutions and doesn't for no solutions) So think about what a parabola looks like and how that would effect the vertex.
If the discriminant is < 0 (negative) there are no real solutions, only imaginary because you can not take the square root of a negative.. The parabola would never touch/cross the x-axis. The vertex of the parabola would be above the x-axis for a parabola that extends upward and below the x-axis for a parabola extending downward.
quadratic equation:
x = b ±√(negative number) / 2a
--------------------------------------
If the discriminant = 0 there is only one solution for x. That means the parabola may only touch/cross the x-axis once. Parabolas are symmetrical, so this can only happen if the vertex is on the x-axis.
quadratic equation:
x = b ±√(0) / 2a
---------------------------------------
If the discriminant > 0 (positive) there are two solutions for x so the parabola crosses the x-axis twice. The vertex would be below the x-axis for a parabola extending upward and above the x-axis for a parabola extending downward.
quadratic equation:
x = b ±√(positive number) / 2a
ax^2+bx+c=0,a=0
The sign of the discriminant (expression under square root in quadratic formula) tells you how many solutions there are for x.
A solution for x means the parabola touches/crosses the x-axis. (Once for one solution, twice for two solutions and doesn't for no solutions) So think about what a parabola looks like and how that would effect the vertex.
If the discriminant is < 0 (negative) there are no real solutions, only imaginary because you can not take the square root of a negative.. The parabola would never touch/cross the x-axis. The vertex of the parabola would be above the x-axis for a parabola that extends upward and below the x-axis for a parabola extending downward.
quadratic equation:
x = b ±√(negative number) / 2a
--------------------------------------
If the discriminant = 0 there is only one solution for x. That means the parabola may only touch/cross the x-axis once. Parabolas are symmetrical, so this can only happen if the vertex is on the x-axis.
quadratic equation:
x = b ±√(0) / 2a
---------------------------------------
If the discriminant > 0 (positive) there are two solutions for x so the parabola crosses the x-axis twice. The vertex would be below the x-axis for a parabola extending upward and above the x-axis for a parabola extending downward.
quadratic equation:
x = b ±√(positive number) / 2a
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