Question

plz solve it
who solves first i will mark the brainliest

Answer 1

Hi Mate!!!

In Trangle ADC

Tan ( 60) = 20√3 / AD

√3 = 20√3 / AD

AD = 20


In Trangle ABD

Sin ( @ ) = AD / AB

Sin (@ ) = 20 / 40

Sin (@ ) = 1/ 2

Sin ( @ ) = Sin ( 30 )

@ = 30

@ = theta


Hope it helps

Answer 2

in triangle ADC we have
sin60° = DC/AC = 20√3/AC
√3/2 = 20√3/AC
AC = 40cm = AB
since here AC = ab it is an isosceles triangle
so
angleABD = angleACD
in triangle ADC
angleADC = 180-(90+60) = 30°
hence
angleABD = angleACD = ¤ = 30°