Question

Plz solve my question given in attachment below .

Answer 1

GIVEN √3/5 AND -√3/5 are the zeros of the f(x) = 5x^4 -5x^3 - 33x^2 +3x+ 18

(x-√3/5) and (x+√3/5) are its factors

THEIR PRODUCT

(x)^2 - (√3/5)^2

x^2 - 3/5

TAKING L.C.M.

5x^2 - 3/5=0

g(x)=5x^2-3

Divide p(x) with g(x)

on dividing u get quotient x^2-x-6

DO MIDDLE TERM SPLIT OF QUOIENT

YOU WILL GET (x+2) and (x-3) its factors

EITHER x+2=0

OR

x-3=0

THEREFORE :

ZEREOS ARE √3/5 ,√-3/5 , -2 AND +3

HOPE YOU UNDERSTAND

BEST OF LUCK FOR YOUR BOARD EXAMS 2020