plz solve no. 5 roman 1 and 2
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Answer:
if one angle is 80°
hence, sum of other two angles=100(80°+x+y=180° sum of interior angles of triangle=180°)
x+y=100°
3:7=x:y. (3+7=10)
100/10=10
hence angle x=3×10
x=30°
y=7×10
y=70°
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