Question

plz solve q.18,.................

Answer 1

Hey !!!!

5Cot¢ = 3

cot¢ = 3/5 b/p (base/perpendicular)

By using Pythagoras theorem .

heipotenous= √p² + b²

h = √5² + 3²

h = √25+9

h = √34

hence put the value of b p and h sin¢ = P/h = 5/√34
cos¢ = b/h = 3/√34

Now substitute the value of sin¢ and cos¢ on the given question ..

5sin¢ - 3cos¢ /4sin¢ + 3sin¢

5× 5/√34 - 3×3/√34
-----------------------------
4×5/√34 + 3×3/√34

25/√34 - 9/√34
-----------------------
20/√34 + 9/√34 ..

25 - 9/√34
-----------------
20 + 9/√34

16/29 Answer

Hence ur option' B' is exactly perfectly correct ..

________________________

Hope it helps you !!

@Rajukumar111

Answer 2

Thank u ★★★
#CKC

HOPE IT HELPS