plz solve Q no 5 fast
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hey, mate here is ur Ans
( x²-3x+3)²-(x²-3x+3)=7
x²-3x+3{x²-3x+3-1}=7
=>. x²-3x+3=7. or x²-3x+2=7
=> x²-3x-4=0. or. x²-3x-5=0
( x²-3x+3)²-(x²-3x+3)=7
x²-3x+3{x²-3x+3-1}=7
=>. x²-3x+3=7. or x²-3x+2=7
=> x²-3x-4=0. or. x²-3x-5=0
sandeep187350:
(x-1)(x-2)=x^2-3x+2 hoga na
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