plz solve que 30.........
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Loss in GPE =Mgl.........(1)
Energy Stored in wire (E)given by:
E = (1/2)×Mg×l...........(2).
divide equation (1) by (2)...we get,
GPE/E=2
Energy Stored in wire (E)given by:
E = (1/2)×Mg×l...........(2).
divide equation (1) by (2)...we get,
GPE/E=2
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