Question

Plz solve question 2 of sec A

Answer 1

$2 {x}^{3} - {x}^{2} - 8$

this is the cubic polynomial.

here,

$\alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{0}{2} = 0$

and

$\alpha \beta \gamma = \frac{ - d}{a} \\ \alpha \beta \gamma = \frac{ - ( - 8)}{2} \\ \alpha \beta \gamma = \frac{8}{2} = 4$

so now,

$\frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } = \frac{ \alpha \beta + \beta \gamma + \gamma \alpha }{ \alpha \beta \gamma } \\ \frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } = \frac{0}{4} = 0(ans).$

here is your answer

HOPE IT IS HELPFUL