plz solve question 23 whose answer is =8
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[(2n-4)×90°]/n - 360°/(n+1) =95°,
[(2n-4)(n+1)×18 - 72n]/[n(n+2)] =19°,
[(2n²-2n-4)×18 - 72n]/[n(n+1)] =19°,
[36n²-36n-72 - 72n]/[n(n+1)] =19°,
[36n²-108n-72] =19n²+19n,
36n²-19n²-108n-19n-72=0,
17n²-127n-72=0,
17n²-(136-9)n-72=0,
17n²-136n+9n-72=0,
17n(n-8)+9(n-8)=0,
(n-8)(17n+9)=0,
then
n-8=0,
n=8 (Octagon)
[(2n-4)(n+1)×18 - 72n]/[n(n+2)] =19°,
[(2n²-2n-4)×18 - 72n]/[n(n+1)] =19°,
[36n²-36n-72 - 72n]/[n(n+1)] =19°,
[36n²-108n-72] =19n²+19n,
36n²-19n²-108n-19n-72=0,
17n²-127n-72=0,
17n²-(136-9)n-72=0,
17n²-136n+9n-72=0,
17n(n-8)+9(n-8)=0,
(n-8)(17n+9)=0,
then
n-8=0,
n=8 (Octagon)
suhana3321:
thankuu dear can you solve my recent question which i uploaded todau
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