plz solve question 50.
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ElementPercentage compositionAtomic
weight Relative No. of atoms. Simplest ratio Carbon 14.4 12 14.4/12 = 1.2 1.2/1.2 =1 Hydrogen1.2 1 1.2/1 = 1.21.2/1.2 =1 Chlorine84.5 35.5 84.5/35.5 = 2.38. 2.38/1.2 = 2
Hence empirical formula is CHCl2.
n = Molecular mass/Empirical formula mass
= 168/(12 + 1 + 70)
= 168/83
= 2.
Therefore, molecular formula = (CHCl2)2 = C2H2Cl4.
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ElementPercentage compositionAtomic
weight Relative No. of atoms. Simplest ratio Carbon 14.4 12 14.4/12 = 1.2 1.2/1.2 =1 Hydrogen1.2 1 1.2/1 = 1.21.2/1.2 =1 Chlorine84.5 35.5 84.5/35.5 = 2.38. 2.38/1.2 = 2
Hence empirical formula is CHCl2.
n = Molecular mass/Empirical formula mass
= 168/(12 + 1 + 70)
= 168/83
= 2.
Therefore, molecular formula = (CHCl2)2 = C2H2Cl4.
if my answer is helpful for u then please mark as brain liest
chirag8874695183:
try to understand....... I can't make table here
ya..i know
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