plz solve question no 2 step by step proof
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B is the mid point of AF by converse of mid theoram
BL is parallel to AD (paralellogram ABCD)
traingle FLB and traingle BEA
FB=BA (B is mid ponit )
angle LBF = angle EAB ( corrosponding angle )
L is mid point of FL ( converse of mid theoram )
LB = AE
traingles are congurent by SAS
FL = BE ( CPCT)
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