Question

plz solve question no. 6

Answer 1

let greater number be a
lesser number be b
3 times greater =3a
3a/b =6 +6
3a=6b+6
5b/a =2 +3
5b=2a+3
2a-5b = -3
3a-6b=6
equating both
2a-5b = -3. ×3
3a-6b=6 ×2
6a-15b=-9
6a-12b=12
-3b=-21
b=21/3
b=7
substitute b=7 in equation
3a-6b=6
3a-6(7)=6
3a-42=6
3a=6+42
3a=48
a=48/3
a=16
a=16,b=7 are numbers

Answer 2

hope this will help you