Question

plz solve question nu 151

Answer 1

Let the original price per dozen = Rs. x

The final price per dozen = Rs. (x - 4)

The number of dozens for Rs. 48 in case of original price =

$\frac{48}{x}$

The number of dozens for Rs. 48 in case of final price =

$\frac{48}{x - 4}$

No. of extra items that can be bought = 12

Therefore, number of extra dozens =

$\frac{12}{12} = 1$

So,

$\frac{48}{x - 4} - \frac{48}{x} = 1$

$\frac{4}{x(x - 4)} = \frac{1}{48}$
${x}^{2} - 4x - 192 = 0$

${x}^{2} - 16x + 12x - 192 = 0$

$x(x - 16) + 12(x - 16) = 0$

$(x - 16)(x + 12) = 0$

$x = 16$
or

$x = - 12 \: (not \: possible)$

Therefore, final price per dozen = Rs. 12

$x - 4 = 16 - 4 = 12$

Answer 2

Step-by-step explanation:

your answer is Rs 12 option B