Question

Plz solve questions no 1 .​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Heya!!

F(x) = x²k² - 3xk + 3x - 1

F(x) = x²k² -3x(k - 1 ) - 1

This polynomial has two zero's/roots becoz it's maximum degree is 2.

It is given that it's one root is 1, let it's another root be a.

1 + a = 3 ( k - 1 )/k² ... Equation i

And

1 × a = -1/k²

a = -1/k²

Now, put value of a in above equation we have

1 - 1/k² = 3( k - 1 )/k²

k² - 1 = 3 ( k - 1 )

k² - 3k + 2 = 0

k² - 2k - k + 2 = 0

k ( k - 2 ) -1 ( k - 2 ) = 0

( k -1 ) = 0 OR ( k - 2 ) = 0

k = 1 OR k = 2