Physics, asked by Luckybls, 11 months ago

plz.... solve ........ quetion 8​

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chowkillanagarovgnf7: ans:38.8 rupees, 48 rupees
Luckybls: how???
chowkillanagarovgnf7: is it correct
Luckybls: i dont know
chowkillanagarovgnf7: bro see
Luckybls: as ans is not given

Answers

Answered by chowkillanagarovgnf7
0

since it is for electricity for daily use take the unit as kWh

so

a. P=1,200W=1.2kW

  t=4hrs

  so

  P=energy(electric energy)/t

  Pt=energy

  energy=1.2x4=4.8kWh

  so

  units(kWh)x8=total cost=4.8x8=38.4rupees

  since its for whole month=31x38.4=1190.4

b. P=500W=0.5kWh

   t=12hrs

   Pt=energy=0.5x12=6kWh

   total cost=6x8=48rupees

   whole month cost=31x48=1488rupees

   


Luckybls: u know hindi or not
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anne94: okay .. u said it to the one who answered I guess.so..
Luckybls: matlab chat hindi me karo
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