Math, asked by krittika2007, 10 months ago

Plz solve step by step

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Answered by pranavmofficial2005
0

Answer:

Step-by-step explanation:

i) We know 2m, m^2+1 and m^2-1  form a pythagorean triplet for any number, m>1.

Let's assume

m^2+1 = 37

Then, m^2 = 36 and m = 6.

Now put the value of m

2m = 12

m^2+1 = 37

m2-1 = 35.

The triplets are 37,35 and 12.

ii) 2m= 8/2

= 4

4×4 = 16

16+1= 17

16-1=15

therefore the triplets are 8,17,15

iii) a Pythagorean triplet is represented by the 2m,m square+1 and m square-1

hence the largest number is m square+1

m square+1= 65

m square= 64

m= 8

2 m = 8× 2= 16

m square-1= 64-1=63

therefore answer is 65,16,63

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