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Step-by-step explanation:
i) We know 2m, m^2+1 and m^2-1 form a pythagorean triplet for any number, m>1.
Let's assume
m^2+1 = 37
Then, m^2 = 36 and m = 6.
Now put the value of m
2m = 12
m^2+1 = 37
m2-1 = 35.
The triplets are 37,35 and 12.
ii) 2m= 8/2
= 4
4×4 = 16
16+1= 17
16-1=15
therefore the triplets are 8,17,15
iii) a Pythagorean triplet is represented by the 2m,m square+1 and m square-1
hence the largest number is m square+1
m square+1= 65
m square= 64
m= 8
2 m = 8× 2= 16
m square-1= 64-1=63
therefore answer is 65,16,63
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