Question

plz solve step by step -vessel p contain mixture of wine and water , in which wine is 66 2/3 %mote than water , 20%of the mixture is replaced with same quantity of wine, find the ratio of wine and water in the resultant mixture in vessel​

Answer 1

Answer:

Thus wine and water ratio=84x/16x=21/4

Step-by-step explanation:

Let total wine mixture=100x litre

and water is  y %=yx

then wine=y+200x/3

water + wine=100x

y+y+200x/3=100x

2y=100x-200x/3

2y=100x/3

y=50x/3............(A)

So in the mixture water=50x/3

and wine=100x-50x/3=250x/3

water: wine=50x/3:250x/2=1:5

Now from 100x mixture 20% or 20x mixture is removed

So mixture left =80x

here water left=80x/5=16x

thus total wine becomes=100x-16x=84x

Thus wine and water ratio=84x/16x=21/4